Question

A cuboidal fish tank has a length of 30 cm, a breadth of 20 cm and a height of 20 cm.
The tank is placed on a horizontal table and it is three-quarters full of water.
Find the area of the tank which is in contact with water.​

Answer 1

Step-by-step explanation:

Length =30, breadth =20 and height =20 so, volume of tank=30x20x20=12000cm cube now vol of water=3/4 of vol of cuboid so vol of water=3/4 x 12000=9000cm cube so 30x20xh=9000 so h=15cm so dimension of tank which are in contact with water are:length =30, breadth =20 and height =15....so area if tank which is in contact with water = LSA of tank + area of base of tank. So.. =2(L+B)xH + LxB =2(30+20)x15+30x15 =2100cm square

Answer 2

Given,

Length of tank = 30 cm

Breadth of tank = 20 cm

Height of tank = 20 cm

As the tank is three-quarters full of water

So, the height of water in the tank = (20 x 3)/4 = 15 cm

Hence,

Area of the tank in contact with the water = Area of floor of Tank + Area of 4 walls upto 15 cm

= 30 × 20 + 2 (30 + 20) × 15

= 600 + 2 × 50 × 15

= 600 + 1500 = 2100 cm²

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