A current of 0.5A is drawn by a filament of an electric bulb for 10 minutes. Find the amount of electric charge that flows through the circuit.
Answers
Answered by
13
we know that I=Q/t
∵1min=60sec
then, 10min=?
therefore 10min=600sec
so 0.5=Q/600
now 0.5*600=Q
Q=300C
therefore charge is 300C
∵1min=60sec
then, 10min=?
therefore 10min=600sec
so 0.5=Q/600
now 0.5*600=Q
Q=300C
therefore charge is 300C
Answered by
6
We are given, I = 0.5 A; the = 10 min = 600s.
We have
Q = It
= 0.5 A * 600s
= 300c
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