A current of 0.5A is drawn by a filament of an electric bulb for 10 minutes. Find the amount of electric charge that flows through the circuit.
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Given : I = 0.5 A , t = 10 mins = 600 seconds
solution: Q=I *T
= 0.5* 600
=300 C
solution: Q=I *T
= 0.5* 600
=300 C
Answered by
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Hii...
Given: current (I) = 0.5 A
time (t)= 10 mins = 10*60= 600 sec
Solution: I = Q/ t
Hence, Q= I*t
Therefore , Q= 0.5*600
= 300 coulomb or 300C
Hope it helps.....
Thanks :)
Given: current (I) = 0.5 A
time (t)= 10 mins = 10*60= 600 sec
Solution: I = Q/ t
Hence, Q= I*t
Therefore , Q= 0.5*600
= 300 coulomb or 300C
Hope it helps.....
Thanks :)
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