A cylinderical vessel open at the top has a base diameter 56 cm . If the total cost of painting the outer curved surface of the vessel is rs 352 at the rate of rs 0.2 per 100 cm2,then the height of the vessel is
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we know the CSA of cylinder = 2piR2h
it said open at the top that means = 2piR2h-piR
Radius of cylinderical vessel = 56/2= 28 cm
=2piR2h-piR
=piR(2Rh-1)
=22/7(28*2*h-1)........................1
rate of 100cm2 at the rate of 0.2rs= 352
=352/100*2=0.704
=0.704=piR(2Rh-1)
=7040=22/7*28(56h-1)
=>7040=4982h-88
=>7040+88/4982=h
=>1.4 cm =h
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