Question

Praveen has applied a force of hundred Newton on an object at an angle of 60° the horizontal the object gets displayed to the horizontal direction and 400 joule work is done what is the displacement of the object

Answer 1

work done is equal to force*displacement *cos   degree.

Here work done is 400 joule.

applied force is 100 N.

angle is 60 degree.

w=F*D*cos degree

400=100*D*1/2 ( value of cos 60 degree is 1/2)

50 D=400

D=400/50

Displacement is 8 m.

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Answer 2

Given:

• Force applied = 100 N
• Angle = 60° to horizontal
• Work done is 400 Joules.

To find:

• Displacement of object ?

Calculation:

The work done by a force is represented as :

$\boxed{W = \vec{F} \: . \: \vec{d}}$

$\implies W = | \vec{F}| \times | \vec{d} | \times \cos( \theta)$

• $\theta$ here is 60°.

• Putting necessary value in SI UNITS :

$\implies 400 = 100\times d \times \cos( {60}^{ \circ} )$

$\implies 400 = 100\times d \times \dfrac{1}{2}$

$\implies 4= d \times \dfrac{1}{2}$

$\implies d = 8 \: metres$

So, displacement of the mass is 8 metres.