A family uses a light bulb of 100 w.a fan of 100 w and a heater of 1000 w each for 8 hours a day.if the cost of electricity is rs 3 per unit ,what is the expenditure for the family for june
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Power of Bulb = 100 watt
Power of Fan = 100 watt
Power of HEATER = 1000 Watt
NOW total energy consumed = (total power)×(total time)
= (100+100+1000)×(8×31)
= (1200)×( 248) = 297600 watt-hours
or 297.6 kwh
or 297.6 units
Now, cost of one unit is = 3 Rs
thus cost of 297.6 units will be = 297.6 ×3 = 892.8 Rs
Power of Fan = 100 watt
Power of HEATER = 1000 Watt
NOW total energy consumed = (total power)×(total time)
= (100+100+1000)×(8×31)
= (1200)×( 248) = 297600 watt-hours
or 297.6 kwh
or 297.6 units
Now, cost of one unit is = 3 Rs
thus cost of 297.6 units will be = 297.6 ×3 = 892.8 Rs
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