A force is given by
![f = at + {bt}^{2} (\: where \: t \: is \: the \: time) f = at + {bt}^{2} (\: where \: t \: is \: the \: time)](https://tex.z-dn.net/?f=+f+%3D+at+%2B+%7Bbt%7D%5E%7B2%7D++%28%5C%3A+where+%5C%3A+t+%5C%3A+is+%5C%3A+the+%5C%3A+time%29)
find dimensions of a and b
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The dimension formula of force is - M¹L¹T^-2
Then the dimension formula of at and bt should be equal to this
So at =M¹L¹/TO
If t is the time then
aT =M¹L¹/T²
A=M¹L¹/T³
And for be it will same
So
bt=M¹L¹/T²
bT²=M¹L¹/T²
b=M¹L¹/T⁴
Then the dimension formula of at and bt should be equal to this
So at =M¹L¹/TO
If t is the time then
aT =M¹L¹/T²
A=M¹L¹/T³
And for be it will same
So
bt=M¹L¹/T²
bT²=M¹L¹/T²
b=M¹L¹/T⁴
Aditya090104:
how is at equal to M1L1T0
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