The distance covered by a particle in time t is given by x = a + bt + ct² + dt³;find the dimensions of a, b, c and d.
Concept of Physics - 1 , HC VERMA , Chapter "Introduction to Physics".
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377
Hello Dear.
Given Equation ⇒
x = a + bt + ct² + dt³
∵ The given equation have Five different terms namely x, a, b, c, d and t.
All of the Terms must have the same dimension of length to give the final dimension([x]) in length.
∴ [x] = L
Also, [bt] = L
⇒ b = L/T
⇒ b = LT⁻¹
Also, [ct²] = L
⇒ c = L/T²
⇒ c = LT⁻²
Also, [dt³] = L
⇒ d = L/T³
⇒ d = LT⁻³
[Note → Dimension of x = L & Dimension of t = T]
Hope it helps.
Given Equation ⇒
x = a + bt + ct² + dt³
∵ The given equation have Five different terms namely x, a, b, c, d and t.
All of the Terms must have the same dimension of length to give the final dimension([x]) in length.
∴ [x] = L
Also, [bt] = L
⇒ b = L/T
⇒ b = LT⁻¹
Also, [ct²] = L
⇒ c = L/T²
⇒ c = LT⁻²
Also, [dt³] = L
⇒ d = L/T³
⇒ d = LT⁻³
[Note → Dimension of x = L & Dimension of t = T]
Hope it helps.
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