Question

A force of 0.1176 N acts horizontally for 5 s on a 50 g
block, kept on a floor. What is the velocity attained by
the block? Coefficient of sliding friction between the
block and the floor is 0.2.
(196 cm. s-1)​

Answer 1

Answer:

N

′

=8g+N

N=2g

∴N

′

=10g

=100 Newtons

Now the maximum possible value of friction force on block B=N

′

μ

2

=(100)(0.5)

=50 Newtons

But since f (applied) < friction force