A force of 10 N acts on a body of 2kg for 3 seconds.find the kinetic energy acquired by the body in 3 seconds.
Answers
Answered by
111
If initial velocity is zero
u = 0
WKT F= ma
then
10N = 2* (v-0)/3 (pls simplify by ur self)
⇒v=15 m/s
then K.E. = [1/2] * m *
K.E. = [1/2] * 2 * 15²
K.E. = 225j
u = 0
WKT F= ma
then
10N = 2* (v-0)/3 (pls simplify by ur self)
⇒v=15 m/s
then K.E. = [1/2] * m *
K.E. = [1/2] * 2 * 15²
K.E. = 225j
amru:
f=[veolcity*mass]/time;velocity=force*time/mass;v=10*3/2=15;KE=1/2*mv^2=1/2*2*
Answered by
37
Given : force =10 N ..Mass = 2kg ....Time = 3s........
To find :- Kinetic energy............
Sol :- E (K) =1/2 ×m ×v (sq.).......... ..Let us find the acceleration for this object.......... Force = mass × acceleration. .....acceleration = force / mass....... = 10/2 = 5m/s....acceleration = 5 m/s......... Now find the velocity...... v = u-v / 2........so, we get as
V= 0-5/2....= 5/2...= 2.5 m/s....is the velocity..... Now E (K) = 1 / 2 × M × V ( SQ).....
1/2 × 3 × 2.5 ...= 3.75 joule..!!
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