Question

a gas at a pressure of 5 atm is heated from 0° to 546°C and simultaneously compressed to 1/3rd of its original volume. hence final pressure is

Answer 1

let take the original volume as( v) and the compressed volume as v/3 then apply the boyel law

Answer 2

Answer: The final pressure is 45 atm.

Explanation: Using ideal gas equation:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

$P_1$ = initial pressure = 5 atm

$V_1$= initial volume = V

$T_1$= initial temperature =$0^0C=(0+273)K=273K$

$P_2$= final pressure= ?

$V_2$= final volume =$\frac{V}{3}$

$T_2$= final temperature =$546^0C=(546+273)K=819K$

$\frac{5\times V}{273}=\frac{P_2\times \frac{V}{3}}{819}$

$P_2=45atm$