Physics, asked by gudimetlarishi1327, 1 year ago

A gas at pressure p has volume v. it is adiabatically compressed to v/32. if (32)^1.4=128, what is the pressure of the gas

Answers

Answered by afridi7
1
when compression is adiabatic
then
P•V^n = constant
here n= gamma

given

(32)^1.4 = 128
put these values in below formula
P.V^n = C

hence

initially
V = 32
P= 1 atm
and C = 128


then a/q
v = 32 is intial volume

and P" , V" = v/32 = 32/32 = 1 are final

therefore for adiabatic compression

pv = P"V" = C

P" = C/V" = 128/1 = 128 pa

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