A goat is tied to a pole fixed on the corner of a rectangular grassy field of dimensions 60 m ×30 my means of 21 m long rope . find the area of the portion of the field that is grazed by the goat also find the grazed area if the pole is fixed to the midpoint of the length of the field.
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Answered by
25
Given:
Side of the square field = 60*30
Length of the rope, r = 21m
(i) We know:
Area of a sector = θ/360×πr2
∴ Area of the sector = 90/360* 22/7*21*21
= 346.5 cm^2
Thus, the area of the part of the field where the horse can graze is 346.5 CM ^2
(ii) If the pole is fixed at the middle of the side, then the horse can graze in a semicircular region.
∴ Area of the field where the horse can graze = πr2/2
therefore midpoint of length will be 60/2= 30 m
there fore
22/7*30*30/2
therefore the area grazed from the midpoint will 1414.285 m^2
Side of the square field = 60*30
Length of the rope, r = 21m
(i) We know:
Area of a sector = θ/360×πr2
∴ Area of the sector = 90/360* 22/7*21*21
= 346.5 cm^2
Thus, the area of the part of the field where the horse can graze is 346.5 CM ^2
(ii) If the pole is fixed at the middle of the side, then the horse can graze in a semicircular region.
∴ Area of the field where the horse can graze = πr2/2
therefore midpoint of length will be 60/2= 30 m
there fore
22/7*30*30/2
therefore the area grazed from the midpoint will 1414.285 m^2
Chaurasiya1:
answer (ii) ka answer correct nhi hai .
Answered by
33
Answer:693 m^2
Step-by-step explanation: length=60m
Breadth=30m
Area=60m×30m. =1800m^2
Area= one half × π × r^2
=one half × π × 21 × 21
=693 m^2
So, this could be the answer
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