Question

A hemispherical bowl of internal diameter 30cm contains some liquid.This liquid is to be filled into cylindrical shaped bottles each of diameter 5cm,and height 6cm,find the number of bottles necessary to empty the bowl.

Answer 1

Diameter of hemispherical bowl= 30cm
radius= d/2=30/2= 15cm.
Volume of Hemispherical bowl= 2/3πr³
2/3×22/7×15×15×15= 7071.4cm³
Diameter of cylinderical bowl = 5cm
Radius= d/2=5/2=2.5cm
Height of cylinderical bowl=6cm
Therefore,
Volume of cylinderical bowl= πr²h=22/7×2.5×6
= 47.14cm³.
Numbers of cylinderical bowl necessary to empty the hemispherical bowl = Volume of hemispherical bowl/Volume of Cylinderical bowl..
Solve this u will get ur answer..
HOPE IT WILL HELP YOU...

Answer 2

Hey mate..
========

Let the required bottles = x

Internal diameter of hemispherical sphere =30 cm.

Internal radius of hemispherical sphere =30/2

=15 cm.

•°• Volume of a hemisphere = $\frac{2}{3}\pi \: r {}^{3} \\ \\ = \frac{2}{3} \pi \times 15 \times 15 \times 15 \\ \\ = 2250\pi \: cm {}^{3}$

Also,

Diameter of the cylindrical bottle = 5cm

 Radius of the cylindrical bottle, r = 5/2 cm and 

Height of the cylindrical bottle, h =  6 cm

 Volume of 1 cylindrical bottle = $\pi \: r {}^{2} h \\ \\ = \pi( \frac{5}{2} ) {}^{2} \times 6 \\ \\ = 37.5\pi \: cm {}^{3}$

Now,

 Amount of water in x bottle = Amount of water in bowl 

i.e. $x \times 37.5\pi = 2250\pi \\ \\ = > x = \frac{2250\pi}{37.5\pi} \\ \\ = > x = \frac{2250 \times 10}{375} \\ \\ = > x = 60$

Hence,

The number of bottles neccessary to empty the bowl is 60

Hope it helps !!