A hemispherical bowl of internal radius 9cm is full of liquid. This liquid is to be filled into cylindrical shaped bottles of diameter 3cm and height 4cm. How many bottles are necessary to empty the bowl?
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Answered by
9
Let the number of bottles required be n.
Therefore, Volume of hemispherical bowl = n *Volume of cylindrical bottle
4/3Πr³=n*Πr²h
4/3*22/7*9*9*9=n*22/7*3/2*3/2*4
4*22*3*9*9/7=n*22*3*3*2/14
21384/7=n*396/14
21384/7=n*198/7
n=21384/198
n=108
Hence,To empty the bowl,108 bottles are required.
Therefore, Volume of hemispherical bowl = n *Volume of cylindrical bottle
4/3Πr³=n*Πr²h
4/3*22/7*9*9*9=n*22/7*3/2*3/2*4
4*22*3*9*9/7=n*22*3*3*2/14
21384/7=n*396/14
21384/7=n*198/7
n=21384/198
n=108
Hence,To empty the bowl,108 bottles are required.
Answered by
6
hemispherical bowl
r=9cm
V=2/3PIr^3
2/3×22/7×9^3
cylindrical bottles
r=1cm
h=4cm
V=PIr^2h
22/7×1^2×4
no. of bottles=(2/3×22/7×9^3) /22/7×1^2×4
now u can calculate answer is 108
r=9cm
V=2/3PIr^3
2/3×22/7×9^3
cylindrical bottles
r=1cm
h=4cm
V=PIr^2h
22/7×1^2×4
no. of bottles=(2/3×22/7×9^3) /22/7×1^2×4
now u can calculate answer is 108
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