Question

A hemispherical bowl of internal radius 9cm is full of water, its contents are emptied in a cylindrical vessel of internal radius 6cm. Find the height of water in a cylindrical vessel.

Answer 1

volume of hemisphere=volume of cylinder
2/3πr^3=πr^2h
2/3×22/7×(9)^3=22/7×6^2×h
h=243/18
h=13.5

Answer 2

Answer:

Height of water in a Cylindrical Vessel = 13.5 cm

Step-by-step explanation:

It is given in question that the content of hemispherical bowl is emptied in a cylindrical vessel. So we can say that,

Volume of hemispherical bowl = Volume of cylindrical vessel    -  (1)

Let h be the height of water in cylindrical vessel.

r (internal radius of hemispherical bowl) = 9 cm

r' (internal radius of cylindrical vessel) =  6 cm

Now, using equation (1)

$\frac{2}{3} \pi r$³ = $\pi$r'²h

$\frac{2}{3} \pi$ * 9 * 9 * 9 = $\pi$ * 6 * 6 * h

2 * 3 * 9 * 9 =  6 * 6 * h

486 = 36 h

13.5 = h

So, the height of water in a cylindrical vessel is 13.5 cm