Question

a. How many digits can be placed in the blank box of a three-digit number
1. Answer the following questions.
?
begins with 67
b. Write all numbers between 60 and 70 that are divisible by 2.
ible by 3 Give the smallest possible vol.​

Answer 1

Answer:

Step-by-step explanation:

Sum of the remaining digits=19

To make the number divisible by 3, the sum of its digits should be divisible by 3.

The smallest multiple of 3 which comes after 19 is 21. Therefore, smallest number=21−19−2

Now, 2+3+3=8

If we put 8, then the sum of the digits will be 27 and as 27 is divisible by 3, the number will also be divisible by 3.

Therefore, the largest number is 8.