Question

A machine gun has a mass of 20 kg . It fires 35 g bullets at the rate of 400 bullets per minute with a speed of 400 m//s What force must be applied to the gun to keep it in position ?

Answer 1

Answer:

Explanation:

Here,Mass Of Machine Gun(m)= 20kg

Mass of each Bullet, (M)=35g=0.035kg

Velocity Of Bullet(v)=400m/s

No.Of Bullets/sec=400/60=20/3

Force required = rate of change of linear momentum of bullets=n(mv)/t

=20/3×(0.035×400)/1=93.3N

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Answer 2

Answer:

mass of gun=20kg=2000g

mass of bullet=35g

velocity of bullet=400m/s

recoil of gun =mass of bullets*velocity of bullet/mass of gun

35*400/2000=-7m/s

therefore a force of 7m/s must be applied to keep the gun in position

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