Question

A man bought two TV sets for Rs 42500. He sold one at a loss of 10% and other at
a profit of 10%. If the selling price of each TV set is same, determine the CP. of
each set. समलिने TV मेट परिषर 42600 को उसने एक TV को 10% बारे में बेच दिया है तथा दूसरे TV
दोनो TV​

Answer 1

Answer:

$\bigstar{\bold{C.P\:of\:first\:T.V=23375\:rupees}}$

$\bigstar{\bold{C.P\:of\:second\:T.V=19125\:rupees}}$

Step-by-step explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Cost of two TV sets = Rs. 42500
• Loss % of first TV set = 10%
• Profit % of second TV set = 10%
• S.P of first TV set = S.P of second T.V set

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• C.P of each T.V set

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Let us take the cost price of the first T.V set as Rs.x

→ Hence by given,

  Cost price of second T.V set = Rs. ( 42500 - x)

→ By given we know that the first T.V set was sold at a loss of 10%

  S.P of first T.V set = x - 10% of x

  S.P of first T.V set = x - 10x/100

  S.P of first T.V set = (100x - 10x)/100

  S.P of first T.V set = 90x/100------(1)

→ Also by given, second T.V set was sold at a profit of 10%

  S.P of second T.V set = 42500 - x + 10% of 42500 - x

  S.P of second T.V set = ( 42500 -x) + 10(42500-x)/100

  S.P of second T.V set = ( 42500 - x ) + 425000 - 10 x/100

  S.P of second T.V set = (4250000 -100x + 425000 - 10x)/100

  S.P of second T.V set = ( 4675000-110x)/100-----(2)

→ By given we know that LHS of equation 1 and 2 is equal, hence RHS must also be equal.

  90x/100 = ( 4675000 - 110x)/100

→ Cancelling 100 on both sides,

  90x = 4675000 - 110x

  110x + 90 x = 4675000

  200x = 4675000

         x = 4675000/200

         x = 23375

→ Hence the cost of first T.V set = Rs. 23375

$\boxed{\bold{C.P\:of\:first\:T.V=23375\:rupees}}$

→ Now we know that C.P of second T.V set = 42500 - x

→ Substitute the value of x

  C.P of second T.V set = 42500 - x

  C.P of second T.V set = Rs.19125

$\boxed{\bold{C.P\:of\:second\:T.V=19125\:rupees}}$