Question

A man lent Rs. 2000 to A at a certain rate and Rs.
250 to B at 2% more rate than that of A. After 3
years he got Rs. 960 at total interest. Find the rate
at which the amount lent to B.​

Answer 1

Answer:

He lent B ₹250 at 16% Rate.

Answer 2

At 16% the amount is lent to B

Step-by-step explanation:

Let the man lent 2000 at the rate of x% per year,

Thus, the interest after 3 years,

$I_1=\frac{2000\times x\times 3}{100}=60x$

If lent amount = 250, rate = (x+2)%,

Then interest,

$I_2=\frac{250\times (x+2)\times 3}{100}=\frac{750(x+2)}{100}=\frac{15(x+2)}{2}$

According to the question,

$I_1+I_2=960$

$60x+\frac{15(x+2)}{2}=960$

$120x + 15x + 30 = 1920$

$135x = 1920-30$

$135x = 1890$

$\implies x=\frac{1890}{135}=14$

∵ x + 2 = 14 + 2 = 16,

Hence, at 16% the amount is lent to B.

#Learn more:

A certain sum of money lent out at simple interest amounts to Rs 1550 in 3 years and Rs 1750 in 5 years find the principal and the rate of interest

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