Question

a man swims 1 km in 10 minuts in the direction of current & 1 km in 30 minutes against the direction of the current . what is the speed of the current?.

Answer 1

Let the speed of the water current be ‘x’ km/min, that of swimmer be ‘y'.

While swimming in the direction of current, net speed of the swimmer: y + x = 1/10 km/min

While swimming against the direction of current, net speed of the swimmer: y - x = 1/30 km/min.

Solving above equations simulteneously, we get....

2y = 4/30…

Hence y = 2/30

and x = 1/30 km/min = 2 km/hr.

plzz mark brainly...

Answer 2

hello.....

✔️Speed of the water current be ‘x’ km/min

✔️speed of swimmer be ‘y'.

✔️net speed of the swimmer(swimming)
=y + x = 1/10 km/min

✔ against the direction of current, net speed of the swimmer(swimming)
=y - x = 1/30 km/min.

equating.....

✔️Therefore we have two equations:—

X+Y=100 — eq.1

X-Y=33.33 — eq.2

✔️✔️Subtracting eq.2 from eq.1....

X - X +Y - (-Y) = 100–33.33

2Y = 66.66…

Y= 66.66/2

Y= 33.33m/min. (approximately values .)
thank you... ..