Question

A moving twin is brought to rest within 30 second by appline breakes .what it's intial velocity if the retardation is 3m/s

Answer 1

Final velocity (v) = 0m/s
Time (t) = 30s
Acceleration = -3m/s^2
Let initial velocity be u
As we know,
Acceleration (a) = (v-u)/t

-3 =(0-u)/30
-3 =-u/30
-90 =-u
u = 90
So, the initial velocity of the twin was 90m/s