Question

a partical starts with a velocity of 5m /s and moves with a uniform auxiliaries of 2.5m/s squre it's velocity after 4s is
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Answer 1

★ Correct Question :

A partical starts with a velocity of 5m /s and moves with a uniform acceleration of 2.5m/s². It's velocity after 4s is

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★ Answer :

• Initial Velocity (u) = 5 m/s
• Acceleration (a) = 2.5 m/s²
• Time (T) = 4 seconds

We know that,

$\boxed{\bf{ Acceleration = \dfrac{Final \ velocity - Initial \ velocity}{Time \ Taken}}}$

_______________[Putting Values]

→ 2.5 = $\sf{\dfrac{v - 5}{4}}$

→ 2.5 $\times$ 4 = v - 5

→ 10 = v - 5

→ v = 10 + 5

→ v = 15 m/s

$\therefore$ Velocity after 4 seconds is 15 m/s.

Answer 2

Answer:

15 m/s

Explanation:

We are provided with:

      Initial velocity(u) = 5 m/s

      Acceleration = 2.5 m/s²

      Time = 4 s

We can apply any equation(of motion) for solutions, but since we have u, a and t (and asked for v),  it will be better to use the 1st equation of motion.

⇒ v = u + at

⇒ v = 5 + (2.5)(4)

⇒ v = 5 + 10

⇒ v = 15 m/s

             ∴ velocity of the particle after 4 second is 15 m/s (in the direction of u)