Question

A particle moves in
straight line with a constant acceleration.It changes its velocity from 10m/s to 20m/s while passing through
a distance of 135m in t seconds. The value of t is______​

Answer 1

Answer:

solution

Applying second eqn of motion, we get

s=ut+2at2...(i)

Also from first eqn of motion,

we have

v−u=at

⇒a=tv−u...(ii)

From (i) and (ii), we get

s=ut+2(v−u)t

⇒s=(2u+v)t

Here, 135=(210+20)t

t=9s