Question

A PD of 250V exist across plates of a 25 micro farad capacitor find charge on each plate​

Answer 1

Answer:

Take the potential difference as the potential of the conductor then solve the answer will come

Hope my answer will help you and please mark me as the brainliest

Answer 2

The charge on each plate is 6.25 × 10-³C

Given:

Potential difference = 250V

Capacitor = 25 micro farad

To Find:

The charge on each plate​

Solution:

The capacitance is calculated as -

Q = CV  

where

Q = Charge stored, C = capacitance, and V = voltage applied.

Substituting the values -

Q =250 × 25 × 10~-6

= 6.25×10~-3

Answer: The charge on each plate is 6.25 × 10-³C

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