A person with his hands in his pocket is skating on ice at the rate of 10 m/s and describes a circle of radius 50 m. What is his inclination to the verticle? (ans : tan^-1(1/5). I need the solution.)
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Answered by
32
this is question is based on concept of circular motion .
at equilibrium conditions ,
Nsin∅ = mv²/r
and Ncos∅ = mg
divide both equation ,
tan∅ = v²/rg
given,
v = 10m/s
r = 50 m
g = 10 m/s²
use this data in above equation,
tan∅ = 100/500 = 1/5
∅ = tan^-1(1/5)
at equilibrium conditions ,
Nsin∅ = mv²/r
and Ncos∅ = mg
divide both equation ,
tan∅ = v²/rg
given,
v = 10m/s
r = 50 m
g = 10 m/s²
use this data in above equation,
tan∅ = 100/500 = 1/5
∅ = tan^-1(1/5)
Answered by
2
tan square -1(1/5)
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