Question

A play ground has the shape of a rectangle, with two semi-circles on its smaller sides as diameters, added to its outside. If the sides of the rectangle are 36 m and 24.5 m, find the area of the playground. (Take π = 22.7).

Answer 1

Answer:

Step-by-step explanation:

Given :

Length of a rectangle = 36 m

Breadth of a rectangle = 24.5 m

Diameter of a semicircle = Breadth of a rectangle = 24.5 m

2r = 24.5  

r = 24.5/2 = 12.25 m

Radius of a semicircle, r = 12.25 m

Area of rectangle,A1 = l ×b

A1 = 36 × 24.5  

A1 = 882 m²

Area of semicircle, A2 = ½ πr²

A2 = ½ × 22/7 × (12.25)²

A2 = 11 × 1.75 × 12.25

A2 = 235.81 m²

Area of playground,A = Area of rectangle + 2 × Area of semicircle

A = A1 + 2 × A2

A = 882 + 2 × 235.81

A = 882 + 471.62

A = 1353.62 m²

Area of playground = 1353.62 m²

Hence, the area of playground is 1353.62 m².

HOPE THIS ANSWER WILL HELP YOU….

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Answer 2

Hey mate..

Answer :

Given:

AB = 36m

BC = 24.5m

Area of rectangular portion = 36×24.5 = 882m2

Radius of semicircular portion =

$\frac{245}{2} = 12.25m$

Area of both semicircular portion =

$= 2 \times \frac{\pi {r}^{2} }{2} \\ \\ = \frac{22}{7 } \times 12.25 \times 12.25 = 471.625$

Area of play ground = 882+471.625 = 1353.62

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