a pole casts a shadow of lenght 2√3m onthe ground when the suns elevation is 60°.find the height of the pole?
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In triangle ABC,
BC is 2√3 m
AB is to be found out
angle C is 60 degrees
tan60 is AB/BC ⇒ √3≈ AB/2√3 ⇒ AB≈ √3* 2√3 ⇒ AB ≈ 6m
Height of pole is 6m
BC is 2√3 m
AB is to be found out
angle C is 60 degrees
tan60 is AB/BC ⇒ √3≈ AB/2√3 ⇒ AB≈ √3* 2√3 ⇒ AB ≈ 6m
Height of pole is 6m
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