a police car is ordered to chase a speeding car which is 5 km ahead and is travelling at an average speed of 80 km/hr.The police car is running at an average speed of 100 Km/hr.How long does it take for the police car to overtake speeding car?
Answers
Answered by
1
S = 5km
u = 80 km/ hr
v = 100 km/ hr
t = ?
= (v - u) ÷ s
=(100 - 80) ÷ 5
= 20 ÷ 5
=4hr
u = 80 km/ hr
v = 100 km/ hr
t = ?
= (v - u) ÷ s
=(100 - 80) ÷ 5
= 20 ÷ 5
=4hr
Answered by
6
Answer:
speed of the speedy car =80km/hr
speed of the police car = 100km/hr
Relative speed = 100 - 80 = 20km/hr
time taken = D / S = 5 / 20 = 1/4hr = 60/4 min.
= 15 min.
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