A purse contains some coins. Of these the number of 1 Rupee coins is 3 times the number of 5 rupees coins and twice the number of 2 rupee coins .If the total number of coins is 66 what is the value of the people???
plzz answer tomorrow is my exam....
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. Let number 1 rupees coin = x
And 2 rupees = y
And 5 rupees = z
Given that
₹1=3×₹5
₹5=2×₹2
Therefore
X= 3*y
Z=2*y
Therefore its given that total number of coins = 66
Therefore
Y+3y+2y=66
6y=66
Y=66/6=11
Number of 2 rupees coin =11
And number of 1 rupees coin = 3 * 11 =33
And number of 5 rupees coin = 2*11= 22
Therefore
The total amount or value = 11 *2 + 33 * 1 + 22 * 5=22+33+110 = 165 rupees
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And 2 rupees = y
And 5 rupees = z
Given that
₹1=3×₹5
₹5=2×₹2
Therefore
X= 3*y
Z=2*y
Therefore its given that total number of coins = 66
Therefore
Y+3y+2y=66
6y=66
Y=66/6=11
Number of 2 rupees coin =11
And number of 1 rupees coin = 3 * 11 =33
And number of 5 rupees coin = 2*11= 22
Therefore
The total amount or value = 11 *2 + 33 * 1 + 22 * 5=22+33+110 = 165 rupees
Hope you liked it
Mark me brainliest
Bye
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