A quadratic polynomial whose zeroes are -3and 4 is
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Explanation :-
Given
Zeroes of the polynomial are - 4 and - 7
So
α = - 4
β = - 7
Sum of zeroes = α + β = - 4 + (-7) = - 4 - 7 = - 11
Product of zeroes = αβ = - 4(-7) = 28
Quadratic polynomial ax² + bx + c
= k{x² - x(α + β) + αβ}
[Where k ≠ 0]
By substituting the values
= k{x² - x(-11) + 28}
= k(x² + 11x + 28)
When k = 1
= 1(x² + 11x + 28)
= x² + 11x + 28
∴ the polynomial whose zeroes are - 4 and - 7 is x² + 11x + 28.
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