A rectangular piece of land is to be fenced for an exhibition. The length of the
is 250 m and its breadth is 200 m. Wen
200 m. We need to keep an entrance of 10 m and an emergency
exit of 5 m. If the cost of this special fencing is rs 175 per metre, what will be the total cost
of fencing?
Answers
AnswEr :
⋆ Reference of Image is in the Attachment
1) Dimension of the Rectangular Land :
- Length ( l ) = 250 m
- Breadth ( b ) = 200 m
2) We need to keep an Entrance of 10 m and an Emergency Exit of 5 m, as shown in the Given Image.
3) Find the Cost of Special Fencing at the rate of Rs. 175 per Metre.
Before Solving this Problem, let me tell you some facts related to it :
◗ If we have to do the fencing of the land then we should must find the Perimeter of the figure, whatever it is.
◗ Perimeter is the outside edge or the limits of the boundaries of any land or figure.
◗ In this Particular Question first we will find the Perimeter of land, then SUBTRACT the length of gates. And finally will find the cost of Special Fencing.
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• Let's Head to the Question Now :
⇒ Perimeter = 2 × ( Length + Breadth )
⇒ Perimeter = 2 × ( 250 m + 200 m )
⇒ Perimeter = 2 × 450 m
⇒ Perimeter = 900 m
this is complete perimeter of the land, now we will find the Perimeter which we have to fence exactly.
• Perimeter to Be Fenced :
⇒ Req. Perimeter = Total Perimeter - Gates
⇒ Req. Perimeter = 900 - (Entrance + Exit)
⇒ Req. Perimeter = 900 - (10 + 5)
⇒ Req. Perimeter = 900 - 15
⇒ Req. Perimeter = 885 m
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• Total Cost of Fencing will be :
⇒ Cost = Req. Perimeter × Rate of Fencing
⇒ Cost = 885 m × Rs. 175
⇒ Cost = 885 × (200 - 25)
⇒ Cost = Rs. (177,000 - 22,125)
⇒ Cost = Rs. 154,875
∴ Cost of Special Fencing is Rs. 154,875
Answer:
=> Cost = Perimeter × Rate
=> Cost = {2(250 + 200) - (10 + 5)} × 175
=> Cost = {2*450 - 15} × 175
=> Cost = {900 - 15} × 175
=> Cost = 885 × 175
=> Cost = Rs. 154,875