Question

a rectangular plot of land measures 41 m in length and 22.5 m in width. A boundary wall 2 m high is built all around the plot at a distance of 1.5 m from the plot. Find the inner surface area of the boundary wall.

Answer 1

please refer to diagram below

dimension of wall A ⇒

                       length = 41 - 1.5 x 2 = 38 m
                       height = 2 m
                       area = 38 x 2 = 76 m²

similarly wall C  = area = 76 m²


now  wall B dimensions ⇒

                                   length = 22.5 - 1.5 x 2 = 19.5 m
                                   height = 2 m
              so                 area = 19.5 x 2 =39 m²

similarly wall D   = area = 39 m²


total surface area of inner wall =  230m²

hope my ans to be correct ...........doubts,ask?