a rectangular plot of land measures 41 m in length and 22.5 m in width. A boundary wall 2 m high is built all around the plot at a distance of 1.5 m from the plot. Find the inner surface area of the boundary wall.
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please refer to diagram below
dimension of wall A ⇒
length = 41 - 1.5 x 2 = 38 m
height = 2 m
area = 38 x 2 = 76 m²
similarly wall C = area = 76 m²
now wall B dimensions ⇒
length = 22.5 - 1.5 x 2 = 19.5 m
height = 2 m
so area = 19.5 x 2 =39 m²
similarly wall D = area = 39 m²
total surface area of inner wall = 230m²
hope my ans to be correct ...........doubts,ask?
dimension of wall A ⇒
length = 41 - 1.5 x 2 = 38 m
height = 2 m
area = 38 x 2 = 76 m²
similarly wall C = area = 76 m²
now wall B dimensions ⇒
length = 22.5 - 1.5 x 2 = 19.5 m
height = 2 m
so area = 19.5 x 2 =39 m²
similarly wall D = area = 39 m²
total surface area of inner wall = 230m²
hope my ans to be correct ...........doubts,ask?
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