A right triangle ABC with sides 3 cm, 4 cm and 5 cm is revolved round the side 4 cm. Find the
volume of the solid so obtained.
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When rt. ∠ed △ABC is revolved about AB = 4 cm, it forms a right circular cone of radius 3 cm and height 4 cm . Slant height of the cone is 5 cm.
Volume of cone = 1 / 3 πr2h
1 / 3 × 22 / 7 × 3 × 3 × 4
= 37.71 cm3
Total surface area of the solid = πr2 + πrl = πr (r + l )
= 22 / 7 × 3 × 8 = 75.43 cm2
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