Question

A rocket is fired from the earth towards the sun. At what distance from the earth's centre is the gravitational force on the rocket zero. mass of sun= 2x 10^30, mass of earth= 6x 10^24. neglect effects of other planets. (orbital radius = 1.5 x 10^11)
pls reply fast .....................

Answer 1

You haven't written the units of the mass and orbital radius.

But I think it is in SI unit.So I am gonna do it with SI unit.

Given,

Mass of the sun=2 × 10^30kg=Ms

Mass of the earth=6 × 10^24kg=Me

orbital radius=1.5×10^11m

Mass of the rocket=m

Now,lets think the distance is r

Let's think that x is the distance from earth's center where the gravitational force on the rocket is zero.

gravitational force of the earth=GmMe/x^2

Gravitational force of the sun=GmMs/(r-x^2)

Using Newton's law,

See the picture above...

Now we can say that the distance is 2.59×10^8.

P.S: I have mistakenly written 60×10^24 in the picture. please excuse that.I did the steps as 6×10^24.

Answer 2

Answer:

Refer the images.Hope it is clear.