Math, asked by Siddhant1687, 1 year ago

A roller 150 CM long has diameter 70cm.
It takes 750 complete revolution. The cost of leveling the playground at the rate of Rs. 2 m square

Answers

Answered by sonukumar985
0
height of cylindrical roller=150cm=(150/100)m=3/2m
diameter of cylindrical roller=70cm
radius of cylindrical roller=70/2=diameter/2=35cm=35/100)m
curved suface area of cylindrical roller=2×pia×r×h=2×22/7×35/100×3/2
=(22×5×3)/100
=(330/100)m^2
=3.3m^2
Area of total revolution=(3.3×750)m^2
=2475m^2
cost of levelling 1m^2=2rs
cost of levelling 2475m^2=(2475×2)rs=4950rs
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