A school gave away 38 medals for honesty, 15 for punctuality and 24 for obedience .If these medals went to a total of 58 students and only 3 students got medals in all the 3 values, how many received medals in exactly two of the three values? Pls solve by Venn Diagram method
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Given
38 medals for honesty.
15 for punctuality and
24 for obedience.
Total Medals = 38 + 15+ 24 = 77
only three students got medals in all the three values,
So, the remaining medal = 77- 9 = 68 medals
Total students =58
So, students who receive exactly 2 medals= 68- 58 = 10 medals
38 medals for honesty.
15 for punctuality and
24 for obedience.
Total Medals = 38 + 15+ 24 = 77
only three students got medals in all the three values,
So, the remaining medal = 77- 9 = 68 medals
Total students =58
So, students who receive exactly 2 medals= 68- 58 = 10 medals
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