Question

A shell of mass 200 g is ejected from a gun of mass 4 kg by an explosion that generates 1.05 kJ of energy. The initial velocity of the shell is

Answer 1

Answer:

Let the initial velocity of the shell be v, then velocity of gun is (0.2v4).  (from conservation of linar moment)

                Now 1.05×103=12(0.2)v2+12(4)(0.2 v4)2   v=100 m/sStraight force is a result of the mass (m) of an item and the speed (v) of the article. On the off chance that an article has higher force, at that point it harder to stop it. The equation for direct force is p = mv. The aggregate sum of force never shows signs of change, and this property is called preservation of energy. Give us a chance to ponder progressively about Linear force and protection of energy.

Answer 2

Answer:

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