a silver cup is plated with silver by passing 965 ampere current for one sevond , the mass of Ag deposited is?
Answers
Answered by
55
965Ampere of current will be equal to 0.01F (1F= 96500amp, so 956amp will be 0.01F)
Therefore,
Mass of Ag deposited will be= 108* 0.01
=1.08grams
Therefore,
Mass of Ag deposited will be= 108* 0.01
=1.08grams
PrincessManshi:
plz mark it as BRAINLIEST if this had really helped u :-)
Answered by
2
Answer:
Explanation:
1.08g
Similar questions
English,
8 months ago
English,
8 months ago
Social Sciences,
1 year ago
History,
1 year ago
Art,
1 year ago
CBSE BOARD X,
1 year ago
Math,
1 year ago