Question

A simple pendulum completes 40 oscillations in a minute. Find its a) frequency b) Time Period

Answer 1

oscillation=40
time taken=60
in 1 sec = 40/60=2/3 Hz  
frequency = 1/time period
time period = 1/frequency
time period = 1/2/3 =3/2 =1.5 sec

i hope it helps...........

Answer 2

Answer:

Frequency is $0.667 \mathrm{~Hz}$and time period is $1.5 \mathrm{~s}$.

Explanation:

• Frequency represents the number of waves that pass a specified place in a provided amount of time.
• The time taken by a particle of medium to achieve its one vibration is named the time period of the wave. or. time period exists the time taken by a vibrating body to achieve one oscillation.

To compute the frequency and period of the pendulum which completes 40 oscillations in a minute, we require to find it utilizing the pendulum formula.

From the question, it is provided that,

Number of Oscillations,

N=40

And Time

t=1min

Currently,

So,

(a) Frequency: It is provided by oscillations per second.

Frequency $f=\frac{N}{t}$

$&=\left(\frac{\text { oscillations }}{60}\right) s^{-1}$

$&=\left(\frac{40}{60}\right) \mathrm{s}^{-1}$

$&=0.667 \mathrm{~Hz}$

(b) Time period: It is provided by 1 upon frequency.

So,

$&\left(\frac{1}{\text { freq }}\right)$

$&=\left(\frac{1}{0.67}\right) \mathrm{s}$

$&=1.5 \mathrm{~s}$

Therefore, frequency is $0.667 \mathrm{~Hz}$and time period is $1.5 \mathrm{~s}$.

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