answer the following question
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(1) x²-6x+8
=> x²-2x-4x+8
=> x(x-2)-4(x-2)
=> (x-4)(x-2)
Area of rectangle = length*breadth
where length > breadth
L*B = (x-4)(x-2)
∴ length = (x-2) units
∴ breadth = (x-4) units
Similarly,
(2)
length = (x-1) units
breadth = (x-2) units
(3)
length = (x-2) units
breadth = (x-5) units
(4)
length = (x+20) units
breadth = (x-1) units
(5)
length = (x+5) units
breadth = (x+4) units
=> x²-2x-4x+8
=> x(x-2)-4(x-2)
=> (x-4)(x-2)
Area of rectangle = length*breadth
where length > breadth
L*B = (x-4)(x-2)
∴ length = (x-2) units
∴ breadth = (x-4) units
Similarly,
(2)
length = (x-1) units
breadth = (x-2) units
(3)
length = (x-2) units
breadth = (x-5) units
(4)
length = (x+20) units
breadth = (x-1) units
(5)
length = (x+5) units
breadth = (x+4) units
narendrakumar58:
means it is applicable to every equation given
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