Question

A solution contains 40 g of common salt in 320 g of water. The concentration in terms of mass by mass percentage of solvent is

Answer 1

Answer:

concentration of the solution=solute/solution×100

=40/(40+320)×100

=40/360×100

=1/9×100

=11.1%

Answer 2

$\huge{\rm{\blue{Question:-}}}$

➛A solution contains 40g of common salt in 320 g of water. Calculate the concentration in terms of mass by mass percentage of the solution.

$\huge{\rm{\blue{Solution:-}}}$

${\rm{\green{ATQ}}}$

${\rm{\orange{→Mass\:of\: solute\:=\:40\:g}}}$

${\orange{\rm{→Mass\:of\: solvent\:=\:320\:g}}}$

${\rm{\green{Formula:-}}}$

${\boxed{\rm{\red{total \: mass \: of \: the \: solution = mass \: of \: solute + mass \: ofsolvent}}}}$

${\rm{\orange{→40g +320g=360g}}}$

${\green{\rm{Formula:-}}}$

${\boxed{\rm{\red{ mass \: \% \: of \: solution = \frac{mass \: of \: solute}{mass \: of \: solution} \times 100 }}}}$

${\orange{\rm{→ \frac{40}{360} \times 100 = 11.1\% }}}$