Question

A spring obeyes hooks law . It require 20 j of work to stretch it through 0.1 m . Find the force constant of spring . Also calculate the work done it further through 0.1m

Answer 1

Explanation:

Answer by:- Mercy

Given, the work required to stretch the spring through 0.1m = 20 J. 

Work done, W1 = F * x = (1/2 * kx) * x =1/2*kx^2 = 0.5*k*0.01 = 20 J 

Therefore, k = 20/0.005 = 4000N/m 

When the spring is further stretched through 0.1 m that is, y = 0.2 

Work done, W2 = ½*(y^2 - x^2) 

=0.5*4000(0.2^2 - 0.1^2) 

= 0.5*4000*(0.04-0.01) 

= 60 J. 

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Answer 2

Answer:

60 J

Explanation:

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