Question

A square shaped coil of side 20 cm is rotating at 60 revolutions per minute in a magnetic field of 100 T. If number of turns is thousand, find maximum emf developed across coil. Give explanation too.

Answer 1

When a coil is turned in constant magnetic field then maximum induced EMF is given by formula

$EMF = -\frac{d\phi}{dt}$

$EMF = NBAw sin(wt +\theta)$

now from above equation the maximum value is defined as

$EMF_{max} = NBAw$

N = number of turns = 1

w = angular speed

$w = 2\pi f = 2*\pi * \frac{60}{60} = 2\pi rad/s$

A = area = 0.2* 0.2 = 0.04 m^2

B = magnetic field = 100 T

Now by above formula

$EMF = 1* 100 * 0.04 * 2\pi$

$EMF = 25.13 Volts$

So maximum value of induced EMF will be 25.13 Volts

Answer 2

Answer:

Explanation:

8π kV