Question

A stone is realised from the top of the tower of hight 19.6m .calculate its final velocity

Answer 1

s=1/gt^2
19.6=1/2(9.8)t^2
t=√3.92
~√4
~2

v=u + at
since,u=0
v=9.8×2
=19.6m/s^2

Answer 2

_/\_Hello mate__here is your answer--

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u = 0 m/s

v = ?

s = Height of the stone = 19.6 m

g = 9.8 ms−2

According to the equation of motion under gravity

v^2 − u^2 = 2gs

⇒ v^2 − 0^2 = 2 × 9.8 × 19.6

⇒ v^2 = 2 × 9.8 × 19.6 = (19.6)^2

⇒ v = 19.6 ms−1

Hence, the velocity of the stone just before touching the ground is 19.6 ms^−1.

I hope, this will help you.☺

Thank you______❤

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