Question

a string of negligible mass going over clamped pulley of mass m and support a block of mass M as shown in the figure. the force on the pulley by the clamp is given.​

Answer 1

Answer:

The answer will be g√(m+M)^2 +(m)^2

Explanation:

According to the problem the mass of the pulley is m and a mass of M is hanged from it.

Now let the tension in the wire is T and the downward force of the pulley is mg and of the mass M is Mg

Now we can say that the tension T is equal and opposite of mg

Now the total force in downwards is f1= (m+M)g

Therefore the resultant force or the force on the pulley given by clamp  is

f = √f1^2+T^2 = √((m+M)g)^2 +(mg)^2 =

                                                    f = g√(m+M)^2 +(m)^2