A student focused the image of a candle flame on a white screen using a concave mirror. He noted down the positions of the candle flame, screen and the mirror as given below:
Position of the candle flame = 12.0cm
Position of the mirror= 50.0 cm
Position of the screen=88.0 cm
(i) the focal length of the concave mirror.
(ii) Find the position of the image of the candle flame if it is shifted towards the mirror at a position of 31.0 cm.
(iii) State the nature of the image formed if the candle flame is further shifted towards the mirror.
Answers
Answer:
Explanation:
(i) object distance u = position of convex lens - position of candle
U = -(50 -12) = -38 cm
image distance v = position of screen -position of convex lens
V-88-50 cm
v- 38 cm
Applying the lens formula:
See 1st image
On calculating focal length will be f-19 cm
(ii) When the candle is shifted towards the lens at a position of 31.0 cm:
Object distance u--(50-31)
U = -19 cm
Applying the lens formula
See 2nd Image
Therefore, v is infinity
(iii). If the candle is further shifted towards the lens, then the nature of the image formed will be virtual, erect and magnified
(iv) The ray diagram will be as follows:
See 3rd Image
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Answer:
V is in infinity.
Explanation:
object distance u = position of convex lens - position of candle
U = -(50 -12) = -38 cm
image distance v = position of screen -position of convex lens
V-88-50 cm
v- 38 cm
Applying the lens formula:
See 1st image
On calculating focal length will be f-19 cm
(ii) When the candle is shifted towards the lens at a position of 31.0 cm:
Object distance u--(50-31)
U = -19 cm
Applying the lens formula
See 2nd Image
Therefore, v is infinity
(iii). If the candle is further shifted towards the lens, then the nature of the image formed will be virtual, erect and magnified