Question

A suitcase is dragged 30m long a floor by a force of 10N inclined at angle 30°to the floor.The work done on the suitcase is
a)150√2j
b)150j
c)150√3j
d)√3j​

Answer 1

$\huge\bigstar\underline\pink{Answer}$

work done on suitcase is w=F.S.cos∅

w = 10× 30× cos 30°

w = 150√3i

or, w = 10×30×sin 30

w = 150j

$\huge\red{\ddot{\smile}}$