Question

a swimming pool in a school is cuvoidal which is 50m long and 44m wide . It is connected with a pipe of diameter 14cm from where water is flowing into the pool at the rate of 15km/h. In what time will the level of water in the pool rise by 21cm..

Answer 1

The answer is 2 hours.
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Answer 2

Answer:

Time taken in which level of water in the pool rise is 2 hours.

Step-by-step explanation:

Given : A swimming pool in a school is cuvoidal which is 50m long and 44m wide . It is connected with a pipe of diameter 14cm from where water is flowing into the pool at the rate of 15km/h.

To find : In what time will the level of water in the pool rise by 21cm?

Solution :

Let the time in which the level of water rise by 21 cm be t hrs.

Diameter of pipe= 14cm

So, radius= 7cm = 0.07m

Rate (h)= 15 km/hr= 15000 m/hr

Volume of water flowing out in 1 h is

$V=\pi r^2 h$

$V=\frac{22}{7}\times (0.07)^2\times 15000$

$V=231m^3$

Now, If the volume of water flowing out in 1 hr is 231 m cube then the volume of water flowing out in t hrs will be 231 t m cube.

Volume of water flowing out in t hrs= Volume of cuboidal pool

$231t=50\times 44\times 0.21$

$231t=462$

$231t=\farc{462}{231}$

$t=2$

Therefore, Time taken in which level of water in the pool rise is 2 hours.