a tiger leaps horizontally from a 7.5-m-high rock with a speed of 3.0 m/s. How far from the base of the rock will she land?
Answers
Answered by
15
The tiger will land 4.6 mtrs from the base of the rock
Explanation:
since the tigers jump doesn't have any vertical motion so it will take the same amount of time as if it would have fallen from the ground,
So from the laws of motion,
S = gt²/2
=> 7.5 = 9.8 t²/2
=> t² = 7.5 x 2 /9.8= 15/9.8 = 1.53 s
Now since in the horizontal trajectory there is no deceleration effect
Hence horizontal distance traveled,
Distance = speed x time = 3 x 1.53 = 4.6 m
Hence the tiger will land 4.6 mtrs from the base of the rock
Answered by
2
Answer:
The answer would be 3.7m
Explanation:
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